0.1x^2+0.4x+1=0

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Solution for 0.1x^2+0.4x+1=0 equation: 



0.1x^2+0.4x+1=0

a = 0.1; b = 0.4; c = +1;
Δ = b2-4ac
Δ = 0.42-4·0.1·1
Δ = -0.24
Delta is less than zero, so there is no solution for the equation

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